For the parabola y = 2x^2 + 3x + 5, what is the y-coordinate where it intersects the y-axis?

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Multiple Choice

For the parabola y = 2x^2 + 3x + 5, what is the y-coordinate where it intersects the y-axis?

Explanation:
To find where a parabola meets the y-axis, set x to zero because the y-axis corresponds to x = 0. Then y equals 2(0)^2 + 3(0) + 5 = 5. So the intersection point is (0, 5), and the y-coordinate is 5. This is because the y-intercept of a quadratic in standard form y = ax^2 + bx + c is the constant term c. Here c is 5, which gives the y-coordinate 5.

To find where a parabola meets the y-axis, set x to zero because the y-axis corresponds to x = 0. Then y equals 2(0)^2 + 3(0) + 5 = 5. So the intersection point is (0, 5), and the y-coordinate is 5. This is because the y-intercept of a quadratic in standard form y = ax^2 + bx + c is the constant term c. Here c is 5, which gives the y-coordinate 5.

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