What is the minimum value of the function p(x) = 576x^2 + 2?

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Multiple Choice

What is the minimum value of the function p(x) = 576x^2 + 2?

Explanation:
Think about what the expression 576x^2 + 2 can be. The square part, 576x^2, is always nonnegative and is zero only when x is zero. So the smallest p(x) you can get is when x = 0, giving p(0) = 576·0^2 + 2 = 2. Any nonzero x makes 576x^2 positive, which increases p(x) above 2. Therefore the minimum value is 2.

Think about what the expression 576x^2 + 2 can be. The square part, 576x^2, is always nonnegative and is zero only when x is zero. So the smallest p(x) you can get is when x = 0, giving p(0) = 576·0^2 + 2 = 2. Any nonzero x makes 576x^2 positive, which increases p(x) above 2. Therefore the minimum value is 2.

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