What is the value of p(0) for p(x) = 576x^2 + 2?

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Multiple Choice

What is the value of p(0) for p(x) = 576x^2 + 2?

Explanation:
Evaluating a polynomial at a specific input means substituting that value for x. In this case, x is 0. Any term that has x (or x^2) becomes 0 when x = 0, so only the constant term remains. So p(0) = 576(0)^2 + 2 = 0 + 2 = 2. The quadratic term vanishes at x = 0, and the constant term 2 is what stays.

Evaluating a polynomial at a specific input means substituting that value for x. In this case, x is 0. Any term that has x (or x^2) becomes 0 when x = 0, so only the constant term remains. So p(0) = 576(0)^2 + 2 = 0 + 2 = 2. The quadratic term vanishes at x = 0, and the constant term 2 is what stays.

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